3x^2+2x-1=x^2-(5-2x^2)

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Solution for 3x^2+2x-1=x^2-(5-2x^2) equation: 



3x^2+2x-1=x^2-(5-2x^2)

We move all terms to the left:

3x^2+2x-1-(x^2-(5-2x^2))=0



We calculate terms in parentheses: -(x^2-(5-2x^2)), so:

x^2-(5-2x^2)

We get rid of parentheses

x^2+2x^2-5

We add all the numbers together, and all the variables

3x^2-5

Back to the equation:

-(3x^2-5)



We add all the numbers together, and all the variables

3x^2+2x-(3x^2-5)-1=0

We get rid of parentheses

3x^2-3x^2+2x+5-1=0

We add all the numbers together, and all the variables

2x+4=0

We move all terms containing x to the left, all other terms to the right

2x=-4

x=-4/2

x=-2

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